The Petri dish shown has no lid. What is the surface area of the outside of the Petri dish?

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Solution

Hint:
Step 1: The surface area of the outside of the petri dish $= 3.14 \times 50 \times 50 + 2 \times 3.14 \times 50 \times 15$
Surface area $= 7850 + 4710$
Surface area $= 12560 m m^{2}$
Final answer: The surface area is $12560 m m^{2}$

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