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Question

The pH of 0.0001 M NaOH is:

A
4
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B
10
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C
12
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D
11
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Solution

The correct option is B 10
NaOH is a strong electrolyte. It completely dissociates in the solution.
[NaOH]=[OH]=0.0001 M.
pOH=log[OH]=log0.0001=4.
But pH+pOH=14.
Hence, pH=14pOH=144=10.

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