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Question
The pH of 0.002M NaOH solution is nearly
A)2.71. B)6.96 C)7.04. D)11.30
The pH of 0.002M NaOH solution is nearly
A)2.71. B)6.96 C)7.04. D)11.30
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Solution
0.002 M NaOH
NaOH ↔ Na+ + OH- [OH-] = NaOH,
[OH-] = 0.002
pOH = -log [OH-] = -log [0.002] = 2.70
Therefore, pH = 14 - 2.70 = 11.30
Therefore answer is d)11.30
0.002 M NaOH
NaOH ↔ Na+ + OH- [OH-] = NaOH,
[OH-] = 0.002
pOH = -log [OH-] = -log [0.002] = 2.70
Therefore, pH = 14 - 2.70 = 11.30
Therefore answer is d)11.30
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