Question

The pH of 0.005 M $H_{2}S{O}_4$ is:

• A. 2.5
• B. 4.5
• C. 2
• D. 1

Answer 1

Answer: (C)

2

$\left[H^{+}\right]=2\times 0.005M=0.01M$
$pH=-log\left[H^{+}\right]=-log0.01=2.0$.