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Question

The pH of 0.005 molar aqueous solution of sulphuric acid is approximately

A
0.005
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B
1
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C
0.1
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D
2.0
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Solution

The correct option is D 2.0
0.005 Molar of aqueous solution sulphuric acid is present, Concentration of protons in acid is written as
[H+]=0.005
pH=log([H+])=log(0.005)=2.301
pH=2.301 approximately 2.

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