Question

The pH of $0.005M{H}_{2}S{O}_4$ acid, if acid is fully dissociated into its ions is

• A. -1
• B. 2
• C. 0
• D. 1

Answer 1

The correct option is B 2

The chemical equation for the above reaction is
$H_{2}S{O}_{4_{\left(aq\right)}}\to 2H_{\left(aq\right)}^{+}+S{O}_4^{2-}$
(0.005M) 2(0.005M) (0.005M)
Concentration of Hydrogen = 2(0.005M)
= 0.01M
$pH=-log\left(H^{+}\right)=-log\left(0.01\right)$
$=-log(1\ast {10}^{-2})$
$=2$