The pH of 0.01M solution of sodium salt of a substituted benzoic acid at 25oC is:
(Ka=1.0×10−4 at 25oC)
A
6
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B
8
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C
10
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D
12
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Solution
The correct option is B8 ArCOONac(1−h)+H2O⇌ArCOOHch+NaOHch ∴[OH−]=ch=c√KHc=√Kw⋅cKa=√10−14×0.0110−4=10−6 [Note:h=√KHc=√10−14×0.0110−4=10−4] ∴1−h≃h ∴pOH=6 and pH=8