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Question

The pH of 0.1 M solution of aniline is 8.8. Its pKb value will be:

A
7.82
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B
6.18
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C
9.40
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D
8.40
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Solution

The correct option is C 9.40
Aniline C6H5NH2 is a weak base.
Given, pH=8.8,c=0.1 M
we know pH+pOH=14
8.8+pOH=14
pOH=148.8=5.2

Also, pOH=pKblog c2
putting the c and pOH values, we get
5.2=pKblog 0.12
10.4=pKblog 0.1
10.4=pKb+1
pKb=10.41
pKb=9.4

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