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Introduction and Degree of Hydrolysis

The pH of 0.1...

Question

The $p H$ of $0.1 M$ solution of aniline is $8.8$ . Its $p K_{b}$ value will be:

7.82

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6.18

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9.40

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8.40

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Solution

The correct option is C $9.40$
Aniline $C_{6} H_{5} N H_{2}$ is a weak base.
Given, $p H = 8.8, c = 0.1 M$
we know $p H + p O H = 14$
$8.8 + p O H = 14$
$p O H = 14 - 8.8 = 5.2$

Also, $p O H = \frac{p K_{b} - l o g c}{2}$
putting the $c$ and $p O H$ values, we get
$5.2 = \frac{p K_{b} - l o g 0.1}{2}$
$10.4 = p K_{b} - l o g 0.1$
$10.4 = p K_{b} + 1$
$p K_{b} = 10.4 - 1$
$p K_{b} = 9.4$

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