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Faraday's First Law

The pH of 1.0...

Question

The pH of 1.0 L of 1.0 M NaCl after the electrolysis for 965 s using 5.0 A current (100% efficiency;log2 = 0.3), is

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Solution

$q = i \times t = 5 \times 965 C = 4825 C = \frac{4825}{96500} F = 0.05 F$
The moles of $O H^{- 1}$ produced = 0.05 moles
[ $O H^{-}$ ]=0.05 (as volume is 1L )
pOH = - log 0.05 = 1.3
pH = 12.70

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