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Question

The pH of 103 M H2SO4 is :

A
3
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B
11.7
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C
2.69
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D
None of the above
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Solution

The correct option is C 2.69
Given, pH=103
After ionisation, H2SO4(aq)2H+(g)+SO24(g)
[H+] from H2SO4 = 2×103 M
we know that pH=log10[H+] pH=log10(2×103=3log102=31.414=2.6989 M)
hence, pH of 103 M H2SO4 is 2.69

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