No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
11.7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2.69
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C 2.69
Given, pH=10−3
After ionisation, H2SO4(aq)⇌2H+(g)+SO2−4(g) [H+] from H2SO4 = 2×10−3M
we know that pH=−log10[H+]pH=−log10(2×10−3=3−log102=3−1.414=2.6989M)
hence, pH of 10−3MH2SO4 is 2.69