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B
11.7
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C
2.69
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D
None of the above
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Solution
The correct option is C 2.69 Given, pH=10−3 After ionisation, H2SO4(aq)⇌2H+(g)+SO2−4(g) [H+] from H2SO4 = 2×10−3M we know that pH=−log10[H+]pH=−log10(2×10−3=3−log102=3−1.414=2.6989M) hence, pH of 10−3MH2SO4 is 2.69