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Question

The pH of 103M NH4OH ( Kb=105) is:

A
3
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B
11
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C
10
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D
4
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Solution

The correct option is C 10
For weak base ammonium hydroxide,
[OH]=kb×c
Substitute values in the above expression,
[OH]=105×103=104 M
pOH=log[OH]=log104=4
pH=14pOH=144=10

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