The pH of 10−8 M HCl solution is
8
7
0
slightly less than 7
[H+] = 10−8 (from HCl) + 10−7 (from water) = 1.1×10−7 M
pH = -log(1.1×10−7) = 6.9
At 25∘C the pH of a 10−8 molar solution of HCl in water is