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Question

The pH of a 0.02 M NH4Cl solution will be:
[Given: Kb(NH4OH)=105 and log2=0.301]

A
2.65
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B
4.35
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C
4.65
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D
5.35
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Solution

The correct option is D 5.35
NH4Cl is a salt of strong acid and weak base. Hence the formula for calculating its pH can be written as
pH=12[pKwpKblogC]
pH=12[14pKblogC]pH=75212(log2×102)pH=5.35

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