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The pH of a 10 ml aqueous solution of HCI is 4. The amount of water to be added to this solution in order to change its pH from 4 to 5 is
The pH of a 10 ml aqueous solution of HCI is 4. The amount of water to be added to this solution in order to change its pH from 4 to 5 is
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Solution
The correct option is B 90 ml
On diIution, mili equivalent of the solute remains constant.
Initially pH of HCI = 4
so normality of HCI =10−4 N
after dilution pH of HCl = 5
so normalityof HCI will be = 10−5 N
N1V1=N2V2
10−4×10=10−5×V
V=100mL
So, 90 mL of water should be added for this pH change.
On diIution, mili equivalent of the solute remains constant.
Initially pH of HCI = 4
so normality of HCI =10−4 N
after dilution pH of HCl = 5
so normalityof HCI will be = 10−5 N
N1V1=N2V2
10−4×10=10−5×V
V=100mL
So, 90 mL of water should be added for this pH change.
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