Question

The $pH$ of a buffer is $6.745$ . When $0.01$ mole of $NaOH$ is added to $1litre$ of it, the $pH$ changes to $6.832$ Its buffer capacity is:

Answer 1

Buffer capacity is the no. of moles of acid or base to be added to $1L$ buffer solution to change its pH by 1 unit.

Buffer Capacity$=\frac{no.ofmolesofO{H}^{-}/H^{+}added}{\left(pHchange\right)\left(Volumeofsolution\right)}$

$=\frac{0.01}{(6.832-6.745)\times 1}=\frac{0.01}{0.087}=0.1209$