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Byju's Answer
Standard XII
Chemistry
Basic Buffer Action
The pH of a...
Question
The
p
H
of a buffer solution prepared by dissolving
30
g
of
N
a
2
C
O
3
in
500
m
L
of an aqueous solution containing
150
m
L
of
1
M
H
C
l
.
K
a
for
H
C
O
−
3
=
5.63
×
10
−
11
is
X
. Nearest integer to X is:
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Solution
N
a
2
C
O
3
+
H
C
l
→
N
a
C
l
+
H
2
C
O
3
Number of moles of
N
a
2
C
O
3
=
W
M
=
30
106
=
0.28
m
o
l
e
s
Number of moles of
H
C
l
=
V
(
L
)
×
M
=
0.15
m
o
l
e
s
Number of moles of
N
a
2
C
O
3
=
0.28
−
0.15
=
0.13
m
o
l
e
s
Concentration of
N
a
2
C
O
3
=
0.13
0.500
+
0.15
Concentration of salt=
0.15
0.500
+
0.15
p
H
of buffer=
p
k
a
+
l
o
g
[
s
a
l
t
]
[
b
a
s
e
]
p
k
a
=
−
l
o
g
[
k
a
]
=
−
l
o
g
[
5.63
×
10
−
11
]
=
10.24
p
H
=
10.24
+
l
o
g
[
0.15
]
[
0.13
]
=
10.32
+
0.062
p
H
=
10.30
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Similar questions
Q.
Calculate the PH of a buffer solution prepared by dissolving 30g of
N
a
2
C
O
3
in 500 ml of an aqueous solution containing 150 ml of 1m
H
C
L
. ka for
H
C
O
−
3
= 5.63 x 10-11
Q.
250
m
L
of a
N
a
2
C
O
3
solution contains
2.65
g
of
N
a
2
C
O
3
⋅
10
m
L
of this solution is added to
x
m
L
of water to obtain
0.001
M
N
a
2
C
O
3
solution. The value of
x
is:
[Molecular weight of
N
a
2
C
O
3
=
106
]
Q.
250 ml of
N
a
2
C
O
3
solution contains 2.65 g of
N
a
2
C
O
3
.10 ml of this solution is mixed with
X
ml of water to obtain 0.001 M
N
a
2
C
O
3
solution. The value of
X
is:
Q.
500
m
L
of
0.2
M
aqueous solution of acetic acid is mixed with
500
m
L
of
0.2
M
H
C
I
at
25
o
C
. If
6
g
of
N
a
O
H
is added to the above solution, determine the final pH (assuming no change in volume on mixing.
K
a
of acetic acid is
1.75
×
10
−
5
m
o
l
L
−
1
. (write the value to the nearest integer)
Q.
100
m
l
of
N
a
2
C
O
3
solution containing
5.3
g
of
N
a
2
C
O
3
was exactly neutralised by
200
m
l
of
H
2
S
O
4
solution. What is the pH of
H
2
S
O
4
?
(
l
o
g
5
=
0.6990
)
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