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Question

The pH of a mixture of 0.01 M HCl and 0.1 M CH3COOH is approximately

A
1
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B
2
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C
4
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D
7
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Solution

The correct option is B 1
Solution:- (A) 1
[H+]=102
[OH]=101
[H+]f=102×1000+101×10001000+1000=5×102
Therefore,
pH=log[H+]
pH=log(5×102)1

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