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Organic Compounds

The pH of a...

Question

The $p H$ of a mono-acidic base is 12.6990. The molarity of the base is:

A

0.02 moles/litre

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B

0.05 moles/litre

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C

0.5 moles/litre

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D

0.2 moles/litre

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Solution

The correct option is A 0.05 moles/litre
$p H + p O H = 14$ .

Thus, $p O H = 14 - p H = 14 - 12.6690 = 1.3310$ .

But, $p O H = - l o g [O H^{-}]$ .

Hence, $[O H^{-}] = 0.05 M$ .

This is equal to the molarity of base.

Option B is correct.

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