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Question

The pH of a mono-acidic base is 12.6990. The molarity of the base is:

A
0.02 moles/litre
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B
0.05 moles/litre
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C
0.5 moles/litre
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D
0.2 moles/litre
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Solution

The correct option is A 0.05 moles/litre
pH+pOH=14.

Thus, pOH=14pH=1412.6690=1.3310.

But, pOH=log[OH].

Hence, [OH]=0.05 M.

This is equal to the molarity of base.

Option B is correct.

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