Question

The $pH$ of a solution of $H_{2}S{O}_4$ is $1$. Assuming complete ionization, find the molarity of $H_{2}S{O}_4$ solution:

• A. $0.1$
• B. $0.2$
• C. $0.05$
• D. $2.0$

Answer 1

Answer: (C)

$0.05$

$pH=-log\left[H_3{O}^{+}\right]=1$

$\left[H^{+}\right]={10}^{-1}M$.

As each mole of acid produces 2 mole of hydrogen ion so molarity of $H_{2}S{O}_4$ is $=0.1/2M=0.05M.$