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Standard XII

Chemistry

Introduction and Degree of Hydrolysis

The pH of an ...

Question

The pH of an aqueous solution of HCl is 3. Its osmotic pressure at a temperature T would be equal to

0.001 RT

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0.002 RT

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3RT

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Solution

The correct option is B
0.002 RT

$H C l \to H^{+} + C l^{-} i = 1 + (n - 1) α = 1 + (2 - 1) \times = 2 [H C l] = 10^{- 3} M π = i C . R . T = 2 \times 10^{- 3} \times R T = 0.002 R T$

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Similar questions

Q. An aqueous solution of sucrose,

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Q. At

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bars at the same temperature, what would be its concentration?

Q. An aqueous solution of sucrose,

C_{12} H_{22} O_{11}

, containing 34.2 g/L has an osmotic pressure of 2.38 atmospheres at

17^{\circ} C

. For an aqueous solution of glucose,

C_{6} H_{12} O_{6}

, to be isotonic with this solution at same temperature, it would have the density:

QUESTION 2.22

At 300 K, 36 g of glucose present in a litre of its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bar at the same temperature, what would be its concentration?

Q. Correct pair of aqueous solutions with equal osmotic pressures at same temperature.

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The pH of an aqueous solution of HCl is 3. Its osmotic pressure at a temperature T would be equal to

The correct option is B 0.002 RT HCl→H++Cl−i=1+(n−1)α=1+(2−1)×=2[HCl]=10−3Mπ=i C.R.T=2×10−3×RT=0.002 RT

The correct option is B
0.002 RT

$H C l \to H^{+} + C l^{-} i = 1 + (n - 1) α = 1 + (2 - 1) \times = 2 [H C l] = 10^{- 3} M π = i C . R . T = 2 \times 10^{- 3} \times R T = 0.002 R T$