The $p H$ of glycine at the first half equivalence point is $2.34$ and that at second half equivalence point is $9.60$ . At the equivalence point (the first inflection point) $p H$ is:

3.63

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2.34

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5.97

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11.94

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Solution

The correct option is C $5.97$
For glycine, at first half equivalence point, $p H = p K_{a_{1}} = 2.34$ .

For glycine, at second half equivalence point, $p H = p K_{a_{2}} = 9.6$ .

Hence, the $p H$ at first equivalence point is:

$p H = \frac{p K_{a_{1}} + p K_{a_{2}}}{2}$

$= \frac{2.34 + 9.6}{2}$

$= 5.97$ .

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The pH of glycine at the first half equivalence point is 2.34 and that at second half equivalence point is 9.60. At the equivalence point (the first inflection point) pH is:

The correct option is C 5.97For glycine, at first half equivalence point, pH=pKa1=2.34.For glycine, at second half equivalence point, pH=pKa2=9.6.Hence, the pH at first equivalence point is:pH=pKa1+pKa22=2.34+9.62=5.97.

The $p H$ of glycine at the first half equivalence point is $2.34$ and that at second half equivalence point is $9.60$ . At the equivalence point (the first inflection point) $p H$ is: