Question

The pH of solution at ${25}^{\circ }C$ which has twice as many hydroxide ion as in pure water at ${25}^{\circ }C$, will be.

• A. $14$
• B. $9$
• C. $6.699$
• D. $7.301$

Answer 1

The correct option is D $7.301$

Given,

Temp = ${25}^0$ C

So, conc. of hydroxide in pure water is ${10}^{-7}M$

A/C to this condition no of hydroxide ion is $2\times {10}^{-7}M$

So, pH = $-log[2\times {10}^{-7}]$

$\Rightarrow$ 7 + 0.301 = 7.301

$\therefore$ pH = 7.301

Hence, option D is correct.