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Question

The pH of the solution 0.1M H2SO4(50mL)+0.4M HCl 50(mL) is:

A
5
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B
7
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C
12
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D
None of these
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Solution

The correct option is D None of these
We first find the individual values of [H+]ion
For 50mL0.1MH2SO4,
[H+]=nαC=210.1=0.2M..........since, acid is strong, α=1
SImilarly, for 50mL0.1MHCl,
[H+]=nαC=110.1=0.1M..........since, acid is strong, α=1
Hence, total [H+]=0.2+0.1=0.3M
pH=log10[H+]=log100.3=0.523
So answer is None of these.(Option D)

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