The correct option is C 7
Find milliequivalents of HCl and NaOH and then find which is in excess to know pH of resulting solution.
Given, vol. of HCl=5 ml, molarity = M/5
Vol. of NaOH=10 mL, molarity = M/10
Milliequivalents of HCl =5×15=1
Milliequivalents of NaOH =10×110=1
HCl+NaOH⟶NaCl+H2O
∵ Milliequivalents of HCl= Milliequivalent of NaOH
∴ Solution is neutral and pH=7