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Question

The pH of the solution containing 10 mL of 0.1 N NaOH and 10 mL of 0.05 N H2SO4 would be:

A
\N
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B
1
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C
>7
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D
7
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Solution

The correct option is C >7
milliequivalent of NaOH=10×0.1=1
milliequivalent of H2SO4=10×0.05=0.5
Left milliequivalent of NaOH=10.5=0.5 M
[OH]=0.510+10=2.5×102
we know the relation
pOH=log[OH]=log(2.5×102)=1.6020
Also,
pH=14pOH
pH=141.6020=12.398

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