Question

The $pH$ of the solution containing $10mL$ of a $0.1MNaOH$ and $10mL$ of $0.05M{H}_{2}S{O}_4$ would be:

• A. $0$
• B. $1$
• C. $>7$
• D. $7$

Answer 1

The correct option is D $7$

$\text{milli-mole of}O{H}^{-}=10\times 0.1=1$

$\text{milli-mole of}{H}^{+}=10\times 0.05\times 2=1$

$\text{Therefore, on mixing the two solutions no mili-mole of solution left thus, pH of solution will be 7}$