The pH of the solution is 2. If its pH is to be raised to 4 then the [H+] of the original solution has to be:
A
doubled
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B
halved
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C
increased by 100 times
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D
decreased by 100 times
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Solution
The correct option is D decreased by 100 times Change in pH is ΔpH=pH2−pH1=4−2=2. Thus ratio of hydrogen ion concentration is [H]+2[H]+1=10−2=0.01. Hence, the hydrogen ion concentration should be decreased by 100 times.