Question

The $pH$ value of $\frac{N}{10}$ $NaOH$ is:

• A. $9$
• B. $10$
• C. $12$
• D. $13$

Answer 1

The correct option is D $13$

$NaOH\to {Na}^{+}+{OH}^{-}$

Normality of $NaOH=$ Molarity of $NaOH=\frac{M}{10}$

$\left[{OH}^{-}\right]={10}^{-1}M$

$\left[H^{+}\right]\left[{OH}^{-}\right]={10}^{-14}$

$\left[H^{+}\right]=\frac{{10}^{-14}}{{10}^{-1}}={10}^{-13}M$

$\therefore$ $pH=-\log {10}^{-13}$

$\therefore$ $pH=13$