The phase difference between alternating emf and current in a purely capacitive circuit will be

zero

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π

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- \frac{π}{2}

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\frac{π}{2}

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Solution

The correct option is A $- \frac{π}{2}$
In purely capacitive circuit current leads the voltage by $π / 2$
So, phase difference between alternating emf and current will be $- π / 2$
[Trick : CCL - capacitor current lead]

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Similar questions

List-I	List- II
(a) Phase difference between current and voltage in a purely resistive AC circuit	(i) π/2; current leads voltage
(b) Phase difference between current and voltage in a pure inductive AC circuit	(ii) zero
(c) Phase difference between current and voltage in a pure capacitive AC circuit	(iii) π/2; current lags voltage
(d) Phase difference between current and voltage in an LCR series circuit	(iv) ${tan}^{- 1} (\frac{X_{C} - X_{L}}{R})$

\frac{π}{2}

The phase difference between alternating current and EMF is π/2 which of the following cannot be constituent of the circuit?

A)LC

B)L

C)C

D)RL

I = \frac{1}{\sqrt{2}} s i n

E = \sqrt{2} s i n (314 t - \frac{Π}{6})

I = \frac{1}{\sqrt{2}} s i n

E = \sqrt{2} s i n (314 t - \frac{Π}{6})

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