Question

The phase difference between current and voltage in an $AC$ circuit is $\frac{\pi }{4}$ radian, if the frequency of $AC$ is $50Hz$, then the phase difference is equivalent to the time difference:-

• A. $0.78s$
• B. $15.7ms$
• C. $2.5s$
• D. $2.5ms$

Answer 1

The correct option is D $2.5ms$

Time Difference = $\frac{Phasedifference}{2\pi \times Frequency}=\frac{\pi /4}{2\pi \times 50}=2.5\times {10}^{-3}sec$

Therefore, D is correct option.