Question

The phase difference between displacement and acceleration of a particle performing S.H.M is

• A. $\frac{\pi }{2}$ rad
• B. $\pi$ rad
• C. $2\pi$ rad
• D. $\frac{3\pi }{2}$

Answer 1

Answer: (B)

$\pi$ rad

Displacement of the particle executing SHM $x=A\sin wt$

Acceleration of the particle $a=\frac{d^{2}x}{d{t}^2}$

$⟹$ $a=-A{w}^2\sin wt=A{w}^2\sin (\pi +wt)$

Thus phase difference between displacement and acceleration of the particle is $\pi$ radian.