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Question

The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is:

A
Zero
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B
0.5π
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C
π
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D
0.707π
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Solution

The correct option is B 0.5π
Let y=Asin ωt
dydx=Aω cosωt
dydx=Aω sin(ωt+π2)
Acceleration=Aω2sinωt
The phase difference between acceleration and velocity is π2 =0.5π

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