Question

The phase difference between the velocity and displacement of a particle executing SHM is

• A. $\pi /2$ radian
• B. $\pi$ radian
• C. $2\pi$ radian
• D. zero

Answer 1

The correct option is A $\pi /2$ radian

$x=Asin(\omega t+\theta )$
$v=dx/dt=A\omega cos(\omega t+\theta )=-A\omega sin(\omega t+\theta +\pi /2)$ since $cos(\pi /2+x)=-sinx$
Thus, phase difference is of $\pi /2$