Question

The phase difference between two points distant $11m$ apart is ${1320}^o$. The frequency of the wave is $105Hz$. The velocity is :

• A. $315m/s$
• B. $4235m/s$
• C. $1155m/s$
• D. $380m/s$

Answer 1

Answer: (A)

$315m/s$

$T=\frac{1}{f}$$=\frac{1}{105}sec$
$T$ is for one complete rotation of ${360}^o$
$t=\frac{T\times 1320}{360}$
$V=\frac{11}{t}$$=\frac{11\times 360}{T\times 1320}$$=\frac{11\times 360\times 105}{1320}$

$V=315m/sec$