The phase difference between two points separated by 0-8 m in a wave of frequency 120 Hz is 0-5 - The wave velocity isA- 144 msB- 384 m - sC- 256 m - sD- 720 m - s

The correct option is B 384 m/sΔ x =0.8 m, n =120 Hz, Δ ϕ =0.5 π Δϕ =2 π/λΔ x or λ =2 π. Δ x/Δϕ =2 π/0.5 π× 0.8 =3.2 m Wave velocity, v = λ =120 × 3.2 =384 m/s ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Frequency

The phase dif...

Question

The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is $0.5 π$ . The wave velocity is

144 ms

No worries! We‘ve got your back. Try BYJU‘S free classes today!

256 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

384 m/s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

720 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 384 m/s
$Δ x = 0.8 m, n = 120 H z, Δ ϕ = 0.5 π$
$Δ ϕ = \frac{2 π}{λ} Δ x$ or $λ = 2 π . \frac{Δ x}{Δ ϕ} = \frac{2 π}{0.5 π} \times 0.8 = 3.2 m$
Wave velocity, $v = λ = 120 \times 3.2 = 384 m / s$

Suggest Corrections

Similar questions

Q. The phase difference between two points separated by 1m in a wave of frequency 120 Hz is

90^{\circ}

. The wave velocity is

Q. The phase difference between two points separated by

0.8 m

in a wave of frequency

120 H z

90

. Then the velocity of wave will be

Q. The phase difference between two points separated by

0.8 m

in a wave of frequency

120 Hz

0.5 π

. The velocity of wave will be

If the frequency of a wave is 360 Hz and the distance between two nearest compression & rarefaction is 1 m. Then the velocity of wave is

In a medium in which a transverse progressive wave is travelling, the phase difference between two points with a separation of 1.25 cm is $(\frac{π}{4})$ . If the frequency of wave is 1000 Hz its velocity will be

Join BYJU'S Learning Program

The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is 0.5π. The wave velocity is

The correct option is C 384 m/sΔx=0.8m,n=120Hz, Δ ϕ=0.5π Δϕ=2πλΔx or λ=2π.ΔxΔϕ=2π0.5π×0.8=3.2m Wave velocity, v=λ=120×3.2=384m/s

The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is $0.5 π$ . The wave velocity is

The correct option is C 384 m/s
$Δ x = 0.8 m, n = 120 H z, Δ ϕ = 0.5 π$
$Δ ϕ = \frac{2 π}{λ} Δ x$ or $λ = 2 π . \frac{Δ x}{Δ ϕ} = \frac{2 π}{0.5 π} \times 0.8 = 3.2 m$
Wave velocity, $v = λ = 120 \times 3.2 = 384 m / s$