The phase difference between two points separated by 0.8m in a wave of frequency 120Hz is 0.5π. The velocity of wave will be
A
720m/s
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B
384m/s
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C
256m/s
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D
144m/s
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Solution
The correct option is B384m/s Given: Path difference, Δx=0.8m Phase difference resulting due to path difference is given by, Δϕ=2πλ×Δx ⇒0.5π=2πλ×0.8 ⇒λ=3.2m Now, wave velocity, v=fλ ⇒v=120×3.2=384m/s