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Question

The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is 0.5π. The velocity of wave will be

A
720 m/s
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B
384 m/s
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C
256 m/s
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D
144 m/s
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Solution

The correct option is B 384 m/s
Given:
Path difference, Δx=0.8 m
Phase difference resulting due to path difference is given by,
Δϕ=2πλ×Δx
0.5π=2πλ×0.8
λ=3.2 m
Now, wave velocity,
v=fλ
v=120×3.2=384 m/s

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