The phase difference between two points separated by 1 m in a wave of frequency 120 Hz is 90- The wave velocity isA- 480 m - sB- 720 m - sC- 180 m - sD- 240 m - s

The correct option is A 480 m/sPath different Δ=λ/2π×ϕ ⇒ 1 =λ/2π×π/2⇒ λ=4m Hence v=nλ= 120× 4=480 m/s ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Mechanical & Non-Mechanical Waves

The phase dif...

Question

The phase difference between two points separated by 1m in a wave of frequency 120 Hz is $90^{\circ}$ . The wave velocity is

180 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

240 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

480 m/s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

720 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 480 m/s
Path different $Δ = \frac{λ}{2 π} \times ϕ \Rightarrow 1 = \frac{λ}{2 π} \times \frac{π}{2} \Rightarrow λ = 4 m$
Hence $v = n λ = 120 \times 4 = 480$ m/s

Suggest Corrections

Similar questions

Q. The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is

0.5 π

. The wave velocity is

If the frequency of a wave is 360 Hz and the distance between two nearest compression & rarefaction is 1 m. Then the velocity of wave is

Q. The phase difference between two points separated by

0.8 m

in a wave of frequency

120 H z

90

. Then the velocity of wave will be

In a medium in which a transverse progressive wave is travelling, the phase difference between two points with a separation of 1.25 cm is $(\frac{π}{4})$ . If the frequency of wave is 1000 Hz its velocity will be

Q. A wave has a frequency of

120 H z

. Two points at a distance of

9 m

apart have a phase difference of

180^{o}

. The velocity of the wave is :

Join BYJU'S Learning Program

The phase difference between two points separated by 1m in a wave of frequency 120 Hz is 90∘ . The wave velocity is

The correct option is C 480 m/sPath different Δ=λ2π×ϕ ⇒ 1 =λ2π×π2⇒ λ=4m Hence v=nλ= 120× 4=480 m/s

The phase difference between two points separated by 1m in a wave of frequency 120 Hz is $90^{\circ}$ . The wave velocity is

The correct option is C 480 m/s
Path different $Δ = \frac{λ}{2 π} \times ϕ \Rightarrow 1 = \frac{λ}{2 π} \times \frac{π}{2} \Rightarrow λ = 4 m$
Hence $v = n λ = 120 \times 4 = 480$ m/s