The phase of a particle in S- H-M- is found to increase by 12- in 6 seconds- Its frequency of oscillations is -

The correct option is D 1 Hz [ Increment of phase by 2π in 6 / 12π #160; · 2π =1 ...

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Standard VIII

Physics

Frequency of sound

The phase of ...

Question

The phase of a particle in $S . H . M .$ is found to increase by $12 π$ in $6$ seconds. Its frequency of oscillations is :

0.5 H z

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2 H z

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2 π H z

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1 H z

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Solution

The correct option is D $1 H z$
$\begin{matrix} I n c r e m e n t o f p h a s e b y 2 π i n \frac{6}{12 π} \cdot 2 π = 1 sec . v = \frac{1}{T} = \frac{1}{1} = 1 H z \end{matrix}$

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The phase of a particle in S.H.M. is found to increase by 12π in 6 seconds. Its frequency of oscillations is :

The correct option is D 1HzIncrementofphaseby2πin612π⋅2π=1sec.v=1T=11=1Hz

The phase of a particle in $S . H . M .$ is found to increase by $12 π$ in $6$ seconds. Its frequency of oscillations is :

The correct option is D $1 H z$
$\begin{matrix} I n c r e m e n t o f p h a s e b y 2 π i n \frac{6}{12 π} \cdot 2 π = 1 sec . v = \frac{1}{T} = \frac{1}{1} = 1 H z \end{matrix}$