Question

The phasor diagram for a component (other than a resistor) connected to an AC source, at an instant, is shown below. The value of voltage across the component and current flowing through the circuit, at this instant, respectively is -

• A. $5\sqrt{3}\text{V},2\sqrt{3}\text{A}$
• B. $5\text{V},2\sqrt{3}\text{A}$
• C. $2\sqrt{3}\text{V},2\text{A}$
• D. $5\sqrt{3}\text{V},2\text{A}$

Answer 1

The correct option is D $5\sqrt{3}\text{V},2\text{A}$

The value of voltage and current at any instant can be calculated from phasor diagram by calculating components of $E_0$ and $i_o$ along the $y-$axis respectively.


Therefore, the current flowing in the circuit at this instant is,

$i=i_0\sin \frac{\pi }{6}=4\times \frac{1}{2}=2\text{A}$

The voltage across the element at this instant is,

$E=E_0\sin (\frac{\pi }{6}+\frac{\pi }{6})=10\sin \frac{\pi }{3}=5\sqrt{3}\text{V}$

Hence, option $\left(D\right)$ is the correct answer.