The phasor diagram of current and voltage for an AC pure resistive circuit is shown below. The resistance of the resistor is

2.5 Ω

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5.5 Ω

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.4 Ω

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Insufficient data

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $2.5 Ω$

For a pure resistive circuit, the resistance of the resistor is given by,

$R = \frac{E_{0}}{i_{0}} = \frac{20}{8} = 2.5 Ω$

Hence, option $(A)$ is the correct answer.

Suggest Corrections

Similar questions

V_{m} s i n ω t

List-I	List- II
(a) Phase difference between current and voltage in a purely resistive AC circuit	(i) π/2; current leads voltage
(b) Phase difference between current and voltage in a pure inductive AC circuit	(ii) zero
(c) Phase difference between current and voltage in a pure capacitive AC circuit	(iii) π/2; current lags voltage
(d) Phase difference between current and voltage in an LCR series circuit	(iv) ${tan}^{- 1} (\frac{X_{C} - X_{L}}{R})$