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Question

The photo cut-off voltage in an experiment was found to be 1.5V. The work function for the material used in the experiment was 4.2 2V. The maximum kinetic energy for the photo electrons that was emitted was

A
1.5eV
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B
2.7eV
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C
4.2eV
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D
5.7eV
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Solution

The correct option is A 1.5eV
Given, cut-off voltage , V0=1.5V
We know that, the maximum kinetic energy of photo electrons is given by , Kmax=eV0=1.5eV

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