The photo cut-off voltage in an experiment was found to be 1.5V. The work function for the material used in the experiment was 4.22V. The maximum kinetic energy for the photo electrons that was emitted was
A
1.5eV
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B
2.7eV
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C
4.2eV
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D
5.7eV
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Solution
The correct option is A1.5eV Given, cut-off voltage , V0=1.5V
We know that, the maximum kinetic energy of photo electrons is given by , Kmax=eV0=1.5eV