The photoelectric threshold frequency of a material is -When light of frequency 4- is incident on the metal- the maximum kinetic energy of the emitted photoelectron is -

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Threshold Frequency

The photoelec...

Question

The photoelectric threshold frequency of a material is $υ$ .When light of frequency $4 υ$ is incident on the metal, the maximum kinetic energy of the emitted photoelectron is :

4 h υ

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3 h υ

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5 h υ

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\frac{5 h υ}{2}

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Solution

The correct option is C $3 h υ$
The maximum kinetic energy of the emitted electrons is given by
$K_{m a x} = h υ - ϕ_{0} = h (4 υ) - h (υ) = 3 h υ$

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The photoelectric threshold frequency of a material is υ.When light of frequency 4υ is incident on the metal, the maximum kinetic energy of the emitted photoelectron is :

The correct option is C 3hυThe maximum kinetic energy of the emitted electrons is given by Kmax=hυ−ϕ0=h(4υ)−h(υ)=3hυ

The photoelectric threshold frequency of a material is $υ$ .When light of frequency $4 υ$ is incident on the metal, the maximum kinetic energy of the emitted photoelectron is :

The correct option is C $3 h υ$
The maximum kinetic energy of the emitted electrons is given by
$K_{m a x} = h υ - ϕ_{0} = h (4 υ) - h (υ) = 3 h υ$