Question

The photoelectric threshold wavelength for a metal surface is 6600 Å. The work function for this is

• A. 1.87 V
• B. 1.87 eV
• C. 18.7 eV
• D. 0.18 eV

Answer 1

The correct option is B

1.87 eV

$W_0=\frac{hc}{\lambda }$

$W_0=\frac{12375}{6600}=1.87eV.$