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Question

The photoelectric threshold wavelength for potassium (work function being 2 eV) is

A
310 nm
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B
620 nm
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C
1200 nm
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D
2100 nm
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Solution

The correct option is B 620 nm
ϕ=hcλt

2eV=1240λTeVnm (hc=1240 eV-nm)

λT=12402nm

=620nm
So, the answer is option (B).

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