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Question

The photoelectric work function for a metal is 4.2eV. If the stopping potential is 3V, find the threshold wavelength and maximum kinetic energy of emitted electrons.
(Velocity of light in air =3×108m/s, Planck's constant =6.63×1034Js, Charge on electron =1.6×1019C)

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Solution

Given : e=1.6×1019C, c=3×108m/s
ϕ=4.2eV, h=6.63×1034J.s, VS=3V
ϕ=4.2×1.6×1019J
=6.72×1019J
(a) Threshold wavelength =λ0=hcϕ
=6.63×1034×3×1086.72×1019
=2.960×107m
=2960˚A
(b) Maximum kinetic energy,
KEmax=eVS=1.6×1019×3
=4.8×1019J

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