The photoelectric work function for a metal surface is 4.125eV. The cut off wavelength for this surface is

3000

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6000

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4125

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2062.5

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Solution

The correct option is A 3000
Work function of metallic substance $ϕ = 4.125 e V$
Cut off wavelength $λ_{m a x} = \frac{h c}{ϕ}$
Or $λ_{m a x} = \frac{1240}{ϕ (i n e V)} n m$
$⟹ λ_{m a x} = \frac{1240}{4.125} = 300 n m = 3000 A^{o}$

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The photoelectric work function for a metal surface is 4.125 eV. The cut-off wavelength for this surface is

6600 \circ A

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