Question

The photograph of a house occupies an area of $1.75c{m}^2$ on a $35\text{mm}$ slide. The slide is projected on to a screen, and the area of the house on the screen is $1.55m^2$. What is the linear magnification of the projector-screen arrangement.

Answer 1

Given: Size of an object = Area of an object =$1.75c{m}^2$

Size of an image = Area of an image = $1.55c{m}^2$

Formula: Arial magnification $\left(m_a\right)=\frac{\text{size of image}}{\text{size of objext}}$

Linear magnification $\left(m_1\right)=\sqrt{m_a}$

$=\frac{1.55m^2}{1.75\times {10}^{-4}{m}^2}$

$=8857$
Linear magnification $\left(m_1\right)=\sqrt{8857}=94.1$